(a) (i) Draw the shape of one of the d orbitals.
- (a)(i)Draw the shape of one of the d orbitals.[1]
- (a)(ii)Complete the following electronic configurations. Ni 1s²2s²2p⁶3s²3p⁶ Ni³⁺ 1s²2s²2p⁶3s²3p⁶[1]
- (b)(i)Complete the diagram to show how the presence of ligands around an isolated transition metal ion affects the energy of the d orbitals. [Figure: Incomplete diagram showing energy levels for 'isolated transition metal ion', 'octahedral complex', 'tetrahedral complex' and 'degenerate d orbitals' label. Two empty boxes for octahedral and tetrahedral splitting.][1]
- (b)(ii)Explain why transition metal complexes are coloured.[2]
- (b)(iii)[Cu(H₂O)₆]²⁺ is pale blue but [Cu(NH₃)₄(H₂O)₂]²⁺ is deep purple-blue. Suggest a reason for this.[1]
- (c)The diagram shows the visible spectrum of a solution of [V(H₂O)₆]³⁺. [Figure: Absorption spectrum showing absorption vs wavelength (nm), with 'blue', 'green', 'red' regions indicated.] State and explain what colour the solution is.[2]
- (d)(i)In the presence of chloride ions, [V(H₂O)₆]³⁺ reacts to form a mixture of isomeric octahedral complexes. [V(H₂O)₆]³⁺ + 2Cl⁻ ⇌ [V(H₂O)₄Cl₂]⁺ + 2H₂O Complete the three-dimensional diagrams to show the two isomers of [V(H₂O)₄Cl₂]⁺. [Figure: Two incomplete octahedral diagrams for isomer 1 and isomer 2.][2]
- (d)(ii)State the type of isomerism shown by isomer 1 and isomer 2 in (i).[1]
- (e)(i)The complex [V(H₂O)₆]³⁺ also reacts with ethane-1,2-diamine (en), H₂NCH₂CH₂NH₂, to form a mixture of isomeric octahedral complexes. [V(H₂O)₆]³⁺ + 3en ⇌ [V(en)₃]³⁺ + 6H₂O Complete the three-dimensional diagrams to show the two isomers of [V(en)₃]³⁺. You may use N N to represent en. [Figure: Two incomplete octahedral diagrams for isomer 1 and isomer 2.][2]
- (e)(ii)State the type of isomerism shown by isomer 1 and isomer 2 in (i).[1]
- (f)(i)The reaction of [Ni(H₂O)₆]²⁺ with aqueous ammonia produces the complex [Ni(NH₃)₆]²⁺. [Ni(H₂O)₆]²⁺(aq) + 6NH₃(aq) ⇌ [Ni(NH₃)₆]²⁺(aq) + 6H₂O(l) Write the expression for Kstab for [Ni(NH₃)₆]²⁺.[1]
- (f)(ii)[Ni(H₂O)₆]²⁺ also reacts with en to form [Ni(en)₃]²⁺. The values of the stability constants for the two complexes are shown. Kstab [Ni(NH₃)₆]²⁺ = 4.8 × 10⁷ mol⁻⁶ dm¹⁸ Kstab [Ni(en)₃]²⁺ = 2.0 × 10¹⁸ mol⁻³ dm⁹ A solution containing equal numbers of moles of ammonia and en is added to [Ni(H₂O)₆]²⁺. State which complex is produced in the larger amount. Explain your answer.[1]
- (f)(iii)Adding a limited amount of en to [Ni(H₂O)₆]²⁺ forms the complex [Ni(H₂O)₂(en)₂]²⁺. Suggest the number of possible stereoisomers of [Ni(H₂O)₂(en)₂]²⁺. Explain your answer. You are advised to include three-dimensional diagrams in your answer.[2]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Feb/Mar 2017). The mark or mark type is shown in brackets.
- [1] diagram of a d-orbital
- [1] Ni: 3d⁸4s² AND Ni³⁺: 3d⁷
- [1] correct splitting of degenerate d orbitals for octahedral and tetrahedral complexes (octahedral: t2g lower, eg higher; tetrahedral: e lower, t2 higher)
- [1] energy/photon is absorbed in the visible region/light
- [1] electron jumps from the lower to the upper energy level/is excited
- [1] different frequency/wavelength of light are absorbed by the two complexes OR different size of energy gap
- [1] colour of solution: green
- [1] explanation: because the solution absorbs most strongly in the blue AND red regions
- [2] correct diagrams showing cis and trans isomers of [V(H2O)4Cl2]+
- [1] cis-trans / geometrical
- [2] correct diagrams showing the two optical isomers of [V(en)3]3+
- [1] optical
- [1] Kstab = [Ni(NH3)62+]/([Ni(H2O)62+][NH3]⁶)
- [1] [Ni(en)3]2+ would be formed because it is much more stable / Kstab is much greater OR in the presence of both ligands the overall equilibrium [Ni(NH3)6]2+ ⇌ [Ni(H2O)6]2+ ⇌ [Ni(en)3]2+ would shift right
- [1] cis-trans isomers identified
- [1] two cis isomers identified (as optical isomers / enantiomers)
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