Aqueous acidified iodate(V) ions, IO3¯, react with iodide ions, as shown. IO3¯ + 6H+ + 5I¯ → 3I2 + 3H2O The initial rate of this reaction is investigated. Table 3.1 shows the results obtained. [Table 3.1] The rate equation for this reaction is rate = k[IO3¯][H+]2[I−]2.
- (a)(i)Explain what is meant by order of reaction.[1]
- (a)(ii)Complete Table 3.2. [Table 3.2][1]
- (a)(iii)Use your answer to (a)(ii) to sketch lines in Fig. 3.1 to show the relationship between the initial rates and the concentrations of [IO3¯] and [I¯]. [Figure 3.1][1]
- (a)(iv)Use data from Table 3.1 to calculate the rate constant, k, for this reaction. Include the units of k.[2]
- (a)(v)Use data from Table 3.1 to calculate the concentration of hydrogen ions, [H+], in experiment 2.[1]
- (a)(vi)This reaction is repeated in two separate experiments. The experiments are carried out at the same temperature and with the same concentrations of I¯ and IO3¯. One experiment takes place at pH 1.0 and the other experiment takes place at pH 2.0. rate at pH 1.0 Calculate the value of . rate at pH 2.0[1]
- (b)In aqueous solution, iron(III) ions react with iodide ions, as shown. 2Fe3+ + 2I- → 2Fe2+ + I2 The initial rate of reaction is first order with respect to Fe3+ and second order with respect to I-. The mechanism for this reaction has three steps. Each step involves only two ions reacting together. Suggest equations for the three steps of this mechanism. Identify the rate-determining step.[3]
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Mark scheme
Marking points from the official mark scheme (May/June 2023). The mark or mark type is shown in brackets.
- [1] the power to which the concentration of a reactant is raised in the rate equation
- [1] the order of reaction with respect to [IO3¯]: 1 the order of reaction with respect to [H+]: 2 the order of reaction with respect to [I-]: 2 the overall order of reaction: 5 All correct for one mark
- [1] (graph showing straight line for [IO3-] vs rate, and upward curve for [I-] vs rate)
- [2] M1 k = rate / [I−]2[IO3¯][H+]² = (4.20 × 10-2)/(0.0252 × 0.04x0.015²) = 7.47 × 106
- [2] M2 units = mol-4 dm12 min-1
- [1] 0.0709 = k x 0.12 × [H+]² × 0.01252 [H+] = 2.25 × 10-2
- [1] x = 102/1 = 100
- [3] M1 step 1 Fe3+ + I− → FeI2+
- [3] M2 step 2 FeI2+ + I− → Fe2+ + I2 OR FeI2+ + I− → FeI2+ AND slowest step = step 2
- [3] M3 step 3 Fe3+ + I2– → Fe2+ + I2 OR FeI2+ + Fe3+ → 2Fe2+ + I2
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