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A-LevelChemistryGroup 29701/42 · May/June 2022 · Q116 Marks

The solubility of the Group 2 hydroxides increases down the group. Explain this trend.

  1. (a)The solubility of the Group 2 hydroxides increases down the group. Explain this trend.[3]
  2. (b)(i)The solubility of Be(OH)2 in water is 2.40 × 10-6gdm⁻³ at 298 K. Write an expression for the solubility product, Ksp, of Be(OH)2 and state its units.[2]
  3. (b)(ii)Calculate the numerical value of Ksp for Be(OH)2 at 298 K.[2]
  4. (c)(i)Be(OH)2 is soluble in aqueous solutions containing an excess of hydroxide ions and forms the complex ion [Be(OH)4]²¯. This complex ion has a similar shape to that of [CuCl4]2-. Define the term complex ion.[1]
  5. (c)(ii)Draw a three-dimensional diagram to show the structure of the complex ion [Be(OH)4]2-. Name the shape of the [Be(OH)4]²- complex ion.[1]
  6. (d)(i)Explain why transition elements can form complex ions.[1]
  7. (d)(ii)Complete Table 1.1 to show the coordination number of each metal ion, and the shapes and overall polarities of the complex ions listed. [Figure Table 1.1][2]
  8. (e)(i)Define stability constant, Kstab.[1]
  9. (e)(ii)Nickel can form complexes with the ligands en, H2NCH2CH2NH2, and tn, H2NCH2CH2CH2NH2, as shown. equilibrium 1 [Ni(H2O)6]2+ + 3en ⇌ [Ni(en)3]2+ + 6H2O Kstab = 6.76 × 1017 equilibrium 2 [Ni(H2O)6]2+ + 3tn ⇌ [Ni(tn)3]2+ + 6H2O Ketab = 1.86 x 1012 Construct an expression for the stability constant, Kstab, for equilibrium 1. State the units for Kstab.[2]
  10. (e)(iii)Describe what the Kstab values indicate about the position of equilibrium for equilibrium 1 and 2. Use the Kstab values to deduce which complex, [Ni(en)3]2+ or [Ni(tn)3]2+, is more stable.[1]

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Mark scheme

Marking points from the official mark scheme (May/June 2022). The mark or mark type is shown in brackets.

  1. [3] M1 ΔHlatt and ΔHhyd both become less exothermic / less negative
  2. [3] M2 ΔHhyd changes less / becomes less exothermic by a smaller extent OR ΔHlatt changes more / dominant factor / changes faster
  3. [3] M3 ΔHsol becomes more exothermic / more negative OR ΔHsol becomes less endothermic / less positive
  4. [2] M1 Ksp = [Be2+][OH-]2
  5. [2] M2 mol³ dm-9 ecf
  6. [2] M1 solubility of Be(OH)2 = 2.40 × 10–6 / 43 = 5.58 × 10-8 (mol dm³) ecf (b)(i)
  7. [2] M2 Ksp = 4 × (5.58 × 10−8)3 = 6.95 × 10–22 ecf min 2sf
  8. [1] as a molecule or ion formed by a central metal atom / metal ion dative bonded to / surrounded by one or more ligands
  9. [1] [Figure of tetrahedral Be(OH)4(2-) structure] tetrahedral and correct 3D structure
  10. [1] d orbitals that are energetically accessible OR empty / vacant d orbitals AND form dative bonds / accept a lone pair from a ligand
  11. [2] [Table values for complex ion: cis-[Pt(en)Cl2] shape: square planar coordination number: 4 polarity: polar; [Ag(NH3)2]+ shape: linear coordination number: 2 polarity: non-polar; [Fe(C2O4)3]3- shape: octahedral coordination number: 6 polarity: non-polar] three for one mark, six for two marks
  12. [1] the equilibrium constant for the formation of the complex ion in a solvent (from its constituent ions or molecules)
  13. [2] M1 Kstab = [Ni(en)32+] / [Ni(H2O)62+][en]3
  14. [2] M1 units = mol-3 dm9 ecf
  15. [1] the equilibria lie to the right / product side OR equilibrium 1 lies more to the right AND en complex is more stable / [Ni(en)3]2+ is more stable

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About this question

Topic
Group 2, A-Level Chemistry (syllabus 9701). Structured question, 16 marks.
Source
A-Level Chemistry, May/June 2022 Paper 4 Variant 2, question 1.

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