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A-LevelChemistryChemical bonding9701/21 · May/June 2021 · Q211 Marks

Carbon monoxide gas, CO(g), and nitrogen gas, N₂(g), are both diatomic molecules. (a) The diagram shows the arrangement of outer electrons in a molecule of CO(g). [Figure X.X]

  1. (a)(i)State one similarity and one difference in the way the atoms in a carbon monoxide molecule are bonded together compared to the atoms in a nitrogen molecule.[2]
  2. (a)(ii)The table states the electronegativity values of carbon, nitrogen and oxygen atoms. electronegativity C 2.5 N 3.0 O 3.5 Use the electronegativity values and relevant details from the Data Booklet to complete the table below. number of electrons per molecule type(s) of intermolecular (van der Waals') force N₂ CO[2]
  3. (b)N₂(g) is less reactive than CO(g) even though N₂(g) has a lower bond energy than CO(g). Suggest why CO(g) is more reactive than N₂(g).[1]
  4. (c)(i)Both carbon monoxide and nitrogen are gases at room temperature and pressure. They both behave like ideal gases under certain conditions. State the two conditions necessary for these two gases to approach ideal gas behaviour.[1]
  5. (c)(ii)Explain why N₂(g) behaves more like an ideal gas than CO(g) does at 20.0°C and 101kPa.[2]
  6. (d)Calculate the amount, in mol, of pure nitrogen gas which occupies 100 cm³ at 101 kPa and 20.0°C. Use relevant information from the Data Booklet. Show your working. Assume nitrogen behaves as an ideal gas. mol[3]

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Mark scheme

Marking points from the official mark scheme (May/June 2021). The mark or mark type is shown in brackets.

  1. [1] M1 both make triple (covalent) bond / 3 shared pairs of electrons
  2. [1] M2 one bond in CO is coordinate / dative covalent / formed by donating a pair of electrons from O (to C)
  3. [2] N2 CO number of electrons per molecule 14 14 type of van der Waals' temporary/instantaneous dipole-induced dipole permanent dipoles- (permanent) dipoles (and temporary/induced / instantaneous dipoles)
  4. [1] CO / it is a polar molecule / it has a (permanent) dipole (but N2 is non-polar)
  5. [1] high temperature AND low pressure
  6. [1] M1 CO is polar/has a permanent dipole OR N2 is non-polar
  7. [1] M2 IMF in CO are (more) significant/ larger OR IMF in N2 are smaller/less significant
  8. [1] Alternative answer M1 (Size of) N2 smaller than CO OR volume of N2 molecules / particles smaller
  9. [1] Alternative answer M2 volume of N2 molecules / particles is more negligible ORA
  10. [1] M1 correct conversion to consistent units P = 101 000 V = 100/1 000 000 = (1 × 10–4) T = 293
  11. [1] M2 use of all values from M1 in correct relationship, n = PV/RT
  12. [1] M3 calculation = 4.15 x 10-3 mol

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About this question

Topic
Chemical bonding, A-Level Chemistry (syllabus 9701). Structured question, 11 marks.
Source
A-Level Chemistry, May/June 2021 Paper 2 Variant 1, question 2.

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