Answer only one of the following two alternatives. EITHER [Figure 11.1 (EITHER)] In the diagram above OA = a, OB = b, OS = (3/5)OA and OT = (7/5)OB. OR [Figure 11.2 (OR)] In the diagram above OC = c and OD = d. The points P and Q lie on OC and OD produced respectively, so that OC : CP = 1 : 2 and OD : DQ = 2 : 1. The line CD is extended to R so that CD = DR.
- (EITHER)(i)Given that AX = µAB, where µ is a constant, express OX in terms of µ, a and b.[2]
- (EITHER)(ii)Given that SX = λST, where λ is a constant, express OX in terms of λ, a and b.[4]
- (EITHER)(iii)Hence evaluate µ and λ.[4]
- (OR)(i)Find, in terms of c and/or d, the vectors OP, OQ and OR.[5]
- (OR)(ii)Show that the points P, Q and R are collinear and find the ratio PQ : QR.[5]
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Mark scheme
Marking points from the official mark scheme (Oct/Nov 2011). The mark or mark type is shown in brackets.
- [M1A1] (EITHER)(i) OX = a + µ(b-a) or (1 − µ)a + µb
- [B1] (EITHER)(ii) OS = 3/5 a
- [B1] (EITHER)(ii) OT = 7/5 b
- [M1A1] (EITHER)(ii) OX = 3/5 a + λ(7/5 b - 3/5 a) or OX = (1-λ)3/5 a + λ7/5 b
- [M1] (EITHER)(iii) Equate components or arrange to (α) a = (β) b and put α = β = 0
- [DM1] (EITHER)(iii) Solve simultaneous equations
- [A1] (EITHER)(iii) λ = 1/2
- [A1] (EITHER)(iii) µ = 7/10
- [B1] (OR)(i) OP = 3c
- [B1] (OR)(i) OQ = 3/2 d
- [B1] (OR)(i) DR = CD = d-c
- [M1A1] (OR)(i) OR = OD + DR = 2d - c
- [M1] (OR)(ii) Finds two of PQ, QR, PR
- [A1+A1] (OR)(ii) Two of PQ = 3/2 d - 3c, QR = 1/2 d - c, PR = 2d - 4c
- [M1] (OR)(ii) Express one vector as multiple of another
- [A1] (OR)(ii) 3:1
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