A particle travels in a straight line so that, t s after passing through a fixed point O, its velocity, vms⁻¹, is given by v = 12cos (t/3).
- (i)Find the value of t when the velocity of the particle first equals 2 ms⁻¹.[2]
- (ii)Find the acceleration of the particle when t = 3.[3]
- (iii)Find the distance of the particle from O when it first comes to instantaneous rest.[4]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2011). The mark or mark type is shown in brackets.
- [M1] (i) Solve cos(t/3) = 2/12
- [A1] (i) 4.21 or 4.2(0)
- [M1] (ii) a = dv/dt = k sin(t/3)
- [A1] (ii) k = -4
- [A1√] (ii) -3.36 or -3.37
- [M1] (iii) Find t when v = 0
- [B1] (iii) s = ∫vdt = 36 sin(t/3)
- [M1] (iii) Substitute t into 36sin(t/3)
- [A1√] (iii) 36
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