Given that the straight line y = 3x + c is a tangent to the curve y = x² + 9x + k, express k in terms of c.
- Given that the straight line y = 3x + c is a tangent to the curve y = x² + 9x + k, express k in terms of c.[4]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2011). The mark or mark type is shown in brackets.
- [1] Eliminates y
- [1] x² + 6x + k − c (= 0)
- [1] Uses b² = 4ac or completes square
- [1] k=c+9
- [1] dy/dx = 2x + 9
- [1] Equate to 3 and solve for x (x = −3)
- [1] Substitute in both equations and equate
- [1] k=c+9
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