O-LevelAdditional MathematicsDifferentiation and integration4037/22 · May/June 2022 · Q127 Marks
A curve is such that d²y/dx² = ((√x+1)/√x)². Given that the gradient of the curve is 4/3 at the point (1, −1), find the equation of the curve.
- A curve is such that d²y/dx² = ((√x+1)/√x)². Given that the gradient of the curve is 4/3 at the point (1, −1), find the equation of the curve.[7]
Mark scheme
Marking points from the official mark scheme (May/June 2022). The mark or mark type is shown in brackets.
- [B2] B1 for (x^4 + x^-4)^2 or x+2√x+1/√x oe seen or for two terms correct in x² + 2 + x^-1/2
- [M1] FT their x²+2+x^-1 providing at least two terms correct and no extra spurious terms
- [M1] dep on previous M1 and having an arbitrary constant; condone one sign or arithmetic slip
- [A1] FT their 10/3
- [M1] dep on previous A1; condone one sign or arithmetic slip
- [A1] y = 4/15 x^2 + x^2 + 4/3 x - 10/3 x - oe
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →