Find the values of the constant k for which (2k-1)x² +6x+k+1 = 0 has real roots.
- Find the values of the constant k for which (2k-1)x² +6x+k+1 = 0 has real roots.[5]
Mark scheme
Marking points from the official mark scheme (May/June 2021). The mark or mark type is shown in brackets.
- M1 Uses b²-4ac: 6²-4(2k-1)(k + 1)
- M1 dep on first M1 -8k²-4k+40 * 0 oe where * is = or any inequality sign condone one sign or arithmetic slip in simplification
- M1 Factorises or solves their 3-term quadratic expression or equation for CVs e.g. (5+2k)(8-4k) oe
- A1 Finds correct CVs: -2.5 oe, 2
- A1 mark final answer -2.5 ≤ k ≤ 2
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →