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O-LevelAdditional MathematicsTrigonometry4037/12 · May/June 2020 · Q107 Marks

Solve tan 3x = -1 for -π/2 ≤ x ≤ π/2 radians, giving your answers in terms of π.

  1. (a)Solve tan 3x = -1 for -π/2 ≤ x ≤ π/2 radians, giving your answers in terms of π.[4]
  2. (b)Use your answers to part (a) to sketch the graph of y = 4 tan 3x + 4 for -π/2 ≤ x ≤ π/2 radians on the axes below. Show the coordinates of the points where the curve meets the axes.[3]

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Mark scheme

Marking points from the official mark scheme (May/June 2020). The mark or mark type is shown in brackets.

  1. [1] For a correct attempt to solve, may be implied by one correct solution
  2. [1] x = -5π/12
  3. [1] x = -π/12
  4. [1] x = π/4
  5. [1] Shape - must have three 'parts' with asymptotes
  6. [1] For correct x-coordinates
  7. [1] For correct y-coordinate

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About this question

Topic
Trigonometry, O-Level Additional Mathematics (syllabus 4037). Structured question, 7 marks.
Source
O-Level Additional Mathematics, May/June 2020 Paper 1 Variant 2, question 10.

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