Solve log₃x+log₉x = 12.
- (a)Solve log₃x+log₉x = 12.[3]
- (b)Solve log₄ (3y² - 10) = 2log₄(y-1) + 1/2.[5]
Mark scheme
Marking points from the official mark scheme (May/June 2019). The mark or mark type is shown in brackets.
- [B1] change to base 3 logarithm log₃x / log₃9
- [M1] simplification and dealing with base 3 logarithms to obtain a power of 3
- [A1] x = 6561
- [B1] use of power rule
- [B1] for log₄2
- [M1] Dep on first two B marks simplification to a three term quadratic.
- [A1] y = 2 only
- [B1] use of division rule
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