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O-LevelAdditional MathematicsDifferentiation and integration4037/22 · May/June 2018 · Q1111 Marks

Find ∫√2x - 1 dx.

  1. (a)Find ∫√2x - 1 dx.[2]
  2. (b)(i)Find ∫sin 4x dx.[2]
  3. (b)(ii)Hence evaluate ∫(π/8)^(π/4) sin 4x dx.[2]
  4. (c)Show that ∫(0)^(ln8) e³ dx = 3.[5]

Mark scheme

Marking points from the official mark scheme (May/June 2018). The mark or mark type is shown in brackets.

  1. [B2] (2x-1)^(3/2) / 3 [+c] oe isw (B1 for k × (2x-1)^(3/2) / (3/2) where k ≠ 0 or for (2x-1)^(3/2) / (3/2) × k where k ≠ 0)
  2. [M1] for k cos 4x [+c] where k < 0 or k = -1/4
  3. [A1] -1/4 cos 4x [+c]
  4. [M1] Sight of correct substitution of limits: -1/4 cos(4π/4) - (-1/4 cos(4π/8)) oe; FT their k cos 4x from (b)(i); dep on M1 awarded in (b)(i)
  5. [A1] 1/4
  6. [M1] For integration leading to k e^(x/3) [+c] (implies k e^(x/3) with k any non-zero constant)
  7. [A1] k = 3
  8. [M1] Sight of correct substitution of limits: their k e^(ln8/3) - their k e^0 oe
  9. [B1] Correct evaluation of e^(ln8/3) as 2
  10. [A1] 6 - 3 = 3

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About this question

Topic
Differentiation and integration, O-Level Additional Mathematics (syllabus 4037). Structured question, 11 marks.
Source
O-Level Additional Mathematics, May/June 2018 Paper 2 Variant 2, question 11.

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