Simplify √x³y¹⁰ ÷ √x³y⁻⁶, giving your answer in the form xᵃyᵇ, where a and b are integers.
- (a)Simplify √x³y¹⁰ ÷ √x³y⁻⁶, giving your answer in the form xᵃyᵇ, where a and b are integers.[2]
- (b)(i)Show that 4(t − 2)³ + 5(t − 2)² can be written in the form (t − 2)ᵖ (qt + r), where p, q and r are constants to be found.[3]
- (b)(ii)Hence solve the equation 4(t − 2)³ + 5(t − 2)² = 0.[1]
Mark scheme
Marking points from the official mark scheme (May/June 2017). The mark or mark type is shown in brackets.
- [B2] x³y⁷ B1 for each term
- [M1] for (t-2)¹ = (t-2)³ (t-2) soi
- [A1] (t-2)(4+5(t-2))
- [A1] (t-2)(5t-6)
- [B1] 2 and 6/5 FT on their (t-2) (5t-6), must have 2
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