The matrix A is (4 5 / 3 2) and the matrix B is (4 2 / 1 3).
- (i)Find the matrix C such that C = 3A + B.[2]
- (ii)Show that det(AB) = det A × det B.[4]
- (iii)Find the matrix (AB)⁻¹.[2]
Mark scheme
Marking points from the official mark scheme (May/June 2016). The mark or mark type is shown in brackets.
- [M1] (12 15 / 9 6) + (4 2 / 1 3) soi if no method shown, may be implied by their answer with at least 2 correct elements
- [A1] (16 17 / 10 9)
- [B1] detA = 4 x 2 - 3 x 5 = -7 or detB = 4 x 3 - 2 x 1 = 10 allow for e.g. (4 x 2 - 3 x 5) x (4 x 3 - 2 x 1) = -70 or detA = 8 - 15 = -7 or detB = 12 - 2 = 10
- [B2] AB = (21 23 / 14 12) or B1 for two elements correct
- [B1] det(AB) = 21 x 12 – 23 x 14 = -70 allow for det(AB) = 252 – 322 = -70
- [B2] 1/(their det AB) x their (12 -23 / -14 21) isw correct or correct FT; FT their AB and their non-zero det AB; their AB must be an attempt at a matrix product e.g. (16 10 / 3 6) B1 for 1/(their det AB) x (their (12 -23 / -14 21)) or for k x their (12 -23 / -14 21)
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →