Find the set of values of x for which 4x² + 19x-5 ≤ 0.
- (a)Find the set of values of x for which 4x² + 19x-5 ≤ 0.[3]
- (b)(i)Express x² + 8x – 9 in the form (x + a)² + b, where a and b are integers.[2]
- (b)(ii)Use your answer to part (i) to find the greatest value of 9 – 8x - x² and the value of x at which this occurs.[2]
- (b)(iii)Sketch the graph of y = 9 - 8x - x², indicating the coordinates of any points of intersection with the coordinate axes. [Figure 9.1][2]
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Mark scheme
Marking points from the official mark scheme (May/June 2015). The mark or mark type is shown in brackets.
- [M1] Solves quadratic
- [A1] critical values 1/4 and -5 soi
- [A1] -5 ≤ x ≤ 1/4 Accept: [-5, 1/4]; -5 ≤ x AND x ≤ 0.25
- [B1,B1] (x+4)²–25 or a = 4 and b = -25
- [B1ft] (Greatest value =) 25 Must be clear
- [B1ft] x = -4
- [B1] Correct shape with maximum in second quadrant and crossing positive and negative axes correctly
- [B1] All 3 intercepts correctly shown on graph
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