Write log₂₇x as a logarithm to base 3.
- (a)Write log₂₇x as a logarithm to base 3.[2]
- (b)Given that logₐy = 3(logₐ15 - logₐ3) + 1, express y in terms of a.[3]
Mark scheme
Marking points from the official mark scheme (May/June 2015). The mark or mark type is shown in brackets.
- [M1] log₃ x / log₃ 27
- [A1] log₃ x / 3 isw NOT log₃ x ÷ 3
- [M1] logₐ 15 - logₐ 3 = logₐ 5 soi
- [M1] logₐ 5³ or logₐ a
- [A1] logₐ y = logₐ 125a ⇒ y = 125a
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