O-LevelAdditional MathematicsLogarithmic and exponential functions4037/22 · Oct/Nov 2020 · Q108 Marks
The number, b, of bacteria in a sample is given by b = P+Qe^(2t), where P and Q are constants and t is time in weeks. Initially there are 500 bacteria which increase to 600 after 1 week.
- (a)Find the value of P and of Q.[4]
- (b)Find the number of bacteria present after 2 weeks.[1]
- (c)Find the first week in which the number of bacteria is greater than 1000000.[3]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2020). The mark or mark type is shown in brackets.
- [B1] (a) P + Q = 500 and P + Qe² = 600
- [M1] (a) Q = 100 / (e² - 1) for attempt to solve by removing P from two equations both containing 3 terms
- [A1] (a) Q = 15.7 or 15.6 awrt
- [A1] (a) P = 484 or 485 awrt
- [B1] (b) B = 484.3 + 15.65e⁴ = 1338 Integer value rounded down from 1338... if seen.
- [M1] (c) e^(2t) = (1000000 - 484.3) / 15.65 Make e^(2t) the subject
- [M1] (c) 2t = ln((1000000 - 484.3) / 15.65) Take logs correctly where e^(2t) > 0 or e^t > 0
- [A1] (c) [t = 5.5(3) or t = 5.5....] → 6th week. nfww
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