An electron is travelling in a vacuum at a speed of 3.4 × 10⁷ ms⁻¹. The electron enters a region of uniform magnetic field of flux density 3.2 mT, as illustrated in Fig. 8.1. The initial direction of the electron is at an angle of 30° to the direction of the magnetic field.
- (a)(i)When the electron enters the magnetic field, the component of its velocity v_N normal to the direction of the magnetic field causes the electron to begin to follow a circular path. Calculate: v_N v_N = ............................................................ ms⁻¹[1]
- (a)(ii)the radius of this circular path. radius = ............................................................ m[3]
- (b)State the magnitude of the force, if any, on the electron in the magnetic field due to the component of its velocity along the direction of the field.[1]
- (c)Use information from (a) and (b) to describe the resultant path of the electron in the magnetic field.[1]
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Mark scheme
Marking points from the official mark scheme (May/June 2019). The mark or mark type is shown in brackets.
- 8(a)(i) VN = 3.4 x 107 x sin 30° A1 = 1.7 x 107 m s-1
- 8(a)(ii) mv² / r = Bqv or r = mv/Bq C1 r = (9.11 × 10–31 × 1.7 × 107) / (3.2 × 10−3 × 1.60 × 10–19) C1 = 0.030 m A1
- 8(b) zero B1
- 8(c) helix/coil B1
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