A cylindrical disc of mass 0.24 kg has a circular cross-sectional area A, as shown in Fig. 3.1. [Figure 3.1 and Figure 3.2] The disc is on horizontal ground, as shown in Fig. 3.2. A force X of magnitude 8.9 N acts on the disc in a direction of 30° to the horizontal. The disc moves at a constant speed of 0.60 m s⁻¹ along the ground.

1. (a)Determine the rate of doing work on the disc by the force X. rate of doing work = ............................................................ W [2][2]
2. (b)The force X and the weight of the disc exert a combined pressure on the ground of 3500 Pa. Calculate the cross-sectional area A of the disc. A = ................................................................. m² [3][3]
3. (c)Newton's third law describes how forces exist in pairs. One such pair of forces is the weight of the disc and another force Y. State:
4. (c)(i)the direction of force Y ......................................................................................................................................... [1][1]
5. (c)(ii)the name of the body on which force Y acts. ......................................................................................................................................... [1][1]

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