4 (a) For a progressive water wave, state what is meant by: (b) Two coherent waves X and Y meet at a point and superpose. The phase difference between the waves at the point is 180°. Wave X has an amplitude of 1.2cm and intensity I. Wave Y has an amplitude of 3.6cm.
- (a)(i)displacement[1]
- (a)(ii)amplitude.[1]
- (b)Calculate, in terms of I, the resultant intensity at the meeting point.[2]
- (c)(i)Monochromatic light is incident on a diffraction grating. Describe the diffraction of the light waves as they pass through the grating.[2]
- (c)(ii)A parallel beam of light consists of two wavelengths 540nm and 630nm. The light is incident normally on a diffraction grating. Third-order diffraction maxima are produced for each of the two wavelengths. No higher orders are produced for either wavelength. Determine the smallest possible line spacing d of the diffraction grating.[3]
- (c)(iii)The beam of light in (c)(ii) is replaced by a beam of blue light incident on the same diffraction grating. State and explain whether a third-order diffraction maximum is produced for this blue light.[2]
Mark scheme
Marking points from the official mark scheme (May/June 2019). The mark or mark type is shown in brackets.
- [B1] distance (in a specified direction of particle/point on wave) from the equilibrium position
- [B1] the maximum distance (of particle/point on wave) from the equilibrium position or the maximum displacement (of particle/point on wave)
- [C1] I ∝ A²
- [A1] IR / I = (3.6 – 1.2)² / (1.2)²
- [A1] resultant intensity = 4.0I
- [B1] as wave(s) pass through the slit(s)
- [B1] wave(s) spread (into geometric shadow)
- [C1] nλ = d sin θ
- [C1] 3λ = d sin 90° or 3λ = d
- [A1] d = 3 x 630 × 10⁻⁹ = 1.9 x 10⁻⁶ m
- [M1] wavelength of blue light is shorter (than 540 nm/630 nm/wavelengths of original light)
- [A1] (so) third order diffraction maximum is produced
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