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A-LevelPhysicsDeformation of solids9702/42 · Feb/Mar 2017 · Q710 Marks

(b) In a strain gauge, the increase in resistance ΔR depends on the increase in length ΔL. The variation of ΔR with ΔL is shown in Fig. 7.1. 8 ΔR/Ω 6+ 4 2- 0 0 2 4 6 8 10 ΔL/10⁻⁵ m Fig. 7.1 The strain gauge is connected into a circuit incorporating an ideal operational amplifier (op-amp), as shown in Fig. 7.2. +6.00 VO strain gauge +5 V +2.00 V OVO 153.0 Ω A + -5 V X Y Fig. 7.2

  1. (a)Describe, with a labelled diagram, the structure of a metal-wire strain gauge.[3]
  2. (b)(i)The strain gauge is initially unstrained with resistance 300.0 Ω. Use data from Fig. 7.1 to calculate the increase in length ΔL of the strain gauge that gives rise to a potential of +2.00 V at point A in Fig. 7.2.[3]
  3. (b)(ii)The strain gauge undergoes a further increase in length beyond the value in (b)(i). State and explain which one of the light-emitting diodes, X or Y, will be emitting light.[4]

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Mark scheme

Marking points from the official mark scheme (Feb/Mar 2017). The mark or mark type is shown in brackets.

  1. [B1] correct grid shape (of wire)
  2. [B1] fine wire/foil strip
  3. [B1] plastic/insulating envelope containing the wire
  4. [C1] 2.00/6.00 = 153.0 / (R + 153.0) or 4.00 / 6.00 = R / (R + 153.0) (so R = 306.0)
  5. [C1] ΔR = 306.0 – 300.0 = 6.0 (Ω)
  6. [A1] so ΔL = 8(.0) × 10⁻⁵ m
  7. [B1] R or ΔR increases
  8. [M1] V⁺ < V⁻ or V_A < 2.00 or V⁺ / V_A decreases
  9. [A1] output is negative / –5 V
  10. [A1] diode X emits light/is 'on'

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About this question

Topic
Deformation of solids, A-Level Physics (syllabus 9702). Structured question, 10 marks.
Source
A-Level Physics, Feb/Mar 2017 Paper 4 Variant 2, question 7.

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