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A-LevelPhysicsThermodynamics9702/42 · Feb/Mar 2017 · Q210 Marks

The first law of thermodynamics can be represented by the expression ΔU = q + w. (b) A fixed mass of an ideal gas undergoes a cycle ABCA of changes, as shown in Fig. 2.1. 6.0 pressure/10⁵ Pa A 5.0- 4.0- 3.0- 2.0- 1.0- B C 0+ 0 2.0 4.0 6.0 volume/10⁻⁴ m³ Fig. 2.1

  1. (a)State what is meant by the symbols in the expression. +ΔU +q +w[2]
  2. (b)(i)During the change from A to B, the energy supplied to the gas by heating is 442 J. Use the first law of thermodynamics to show that the internal energy of the gas increases by 265 J.[2]
  3. (b)(ii)During the change from B to C, the internal energy of the gas decreases by 313 J. By considering molecular energy, state and explain qualitatively the change, if any, in the temperature of the gas.[3]
  4. (b)(iii)For the change from C to A, use the data in (b)(i) and (b)(ii) to calculate the change in internal energy.[1]
  5. (b)(iv)The temperature of the gas at point A is 227 °C. Calculate the number of molecules in the fixed mass of the gas.[2]

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Mark scheme

Marking points from the official mark scheme (Feb/Mar 2017). The mark or mark type is shown in brackets.

  1. [B2] +ΔU increase in internal energy
  2. [B2] +q heat (energy) transferred to the system/heating of system
  3. [B2] +w work done on system
  4. [B1] W = pΔV = 5.2 × 10⁵ × (5.0 – 1.6) × 10⁻⁴ (=177J)
  5. [A1] ΔU = q + w = 442 - 177 = 265 J
  6. [B1] no (molecular) potential energy
  7. [B1] internal energy decreases so (total molecular) kinetic energy decreases
  8. [B1] (mean molecular) kinetic energy decreases so temperature decreases
  9. [A1] ΔU + 265 – 313 = 0
  10. [A1] ΔU = 48 J
  11. [C1] pV = NkT or pV = nRT and N = nNA
  12. [A1] 5.2 × 10⁵ × 1.6 × 10⁻⁴ = N × 1.38 × 10⁻²³ × (273 + 227)
  13. [A1] or 5.2 × 10⁵ × 1.6 × 10⁻⁴ = n × 8.31 × (273 + 227) and n = N/ 6.02 × 10²³
  14. [A1] N = 1.2 x 10²²

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About this question

Topic
Thermodynamics, A-Level Physics (syllabus 9702). Structured question, 10 marks.
Source
A-Level Physics, Feb/Mar 2017 Paper 4 Variant 2, question 2.

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