A-LevelPhysicsCapacitance9702/42 · May/June 2018 · Q610 Marks
Explain what is meant by the capacitance of a parallel plate capacitor.
- (a)Explain what is meant by the capacitance of a parallel plate capacitor.[3]
- (b)(i)Three parallel plate capacitors each have a capacitance of 6.0 µF. Draw circuit diagrams, one in each case, to show how the capacitors may be connected together to give a combined capacitance of 9.0 µF,[1]
- (b)(ii)4.0 µF.[1]
- (c)(i)Two capacitors of capacitances 3.0 µF and 2.0 µF are connected in series with a battery of electromotive force (e.m.f.) 8.0 V, as shown in Fig. 6.1. Calculate the combined capacitance of the capacitors.[1]
- (c)(ii)1.Use your answer in (i) to determine, for the capacitor of capacitance 3.0 µF, the charge on one plate of the capacitor,[2]
- (c)(ii)2.the energy stored in the capacitor.[2]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (May/June 2018). The mark or mark type is shown in brackets.
- [M1] capacitance = charge / potential
- [A1] charge is (numerically equal to) charge on one plate
- [A1] potential is potential difference between plates
- [A1] two in series, in parallel with the other (correct symbols)
- [A1] two in parallel connected to one in series (correct symbols)
- [A1] capacitance = 1.2 µF
- [C1] Q = CV
- [A1] = 1.2 x 8.0 = 9.6 µC
- [C1] E = ½QV and V = Q/C or E = ½CV² and V = Q/C or E = ½Q²/C
- [A1] E = ½ (9.6 × 10⁻⁶)²/ (3.0 × 10⁻⁶) = 1.5 x 10⁻⁵ J
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