A stationary firework explodes into three different fragments that move in a horizontal plane, as illustrated in Fig. 2.1. [Figure 2.1] The fragment of mass 3.0M has a velocity of 7.0ms⁻¹ perpendicular to line AB. The fragment of mass 2.0M has a velocity of 6.0 ms⁻¹ at angle θ to line AB. The fragment of mass 1.5M has a velocity of 8.0 ms⁻¹ at angle θ to line AB.
- (a)State the principle of conservation of momentum.[2]
- (b)(i)Use the principle of conservation of momentum to determine θ.[3]
- (b)(ii)Calculate the ratio kinetic energy of fragment of mass 2.0M kinetic energy of fragment of mass 1.5M[2]
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Mark scheme
Marking points from the official mark scheme (May/June 2018). The mark or mark type is shown in brackets.
- [M1] sum/total momentum (of a system of bodies) is constant OR sum/total momentum before = sum/total momentum after
- [A1] for an isolated system or no (resultant) external force
- [C1] (p =) mv or (3.0M × 7.0) or (2.0M × 6.0) or (1.5M × 8.0)
- [C1] 3.0M × 7.0 = 2.0M × 6.0 sinθ + 1.5M × 8.0 sinθ
- [A1] θ = 61°
- OR (vector triangle method)
- (C1) momentum vector triangle drawn
- (A2) θ = 61° (2 marks for ±1°, 1 mark for ±2°)
- OR (use of cosine rule)
- (C1) p = mv or (3.0M × 7.0) or (2.0M × 6.0) or (1.5M × 8.0)
- (C1) (21M)² = (12M)² + (12M)² – (2 × 12M × 12M × cos 2θ)
- (A1) θ = 61°
- [C1] (E =) ½mv²
- [A1] ratio = (½ × 2.0M × 6.0²) / (½ × 1.5M × 8.0²) = 0.75
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