A β⁻ particle from a radioactive source is travelling in a vacuum with kinetic energy 460 eV. The particle enters a uniform electric field at a right-angle and follows the path shown in Fig. 7.1. β⁻ particle kinetic energy 460 eV path of β⁻ particle uniform electric field in the plane of the paper Fig. 7.1
- (a)The direction of the electric field is in the plane of the paper. On Fig. 7.1, draw an arrow to show the direction of the electric field.[1]
- (b)Calculate the speed of the β⁻ particle before it enters the electric field. speed =[3]
- (c)Other β⁻ particles from the same radioactive source travel outside the electric field along the same incident path as that shown in Fig. 7.1. State and briefly explain whether those β⁻ particles will all follow the same path inside the electric field.[2]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
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- [B1] arrow pointing vertically down the page
- [C1] E = ¹/₂mv²
- [C1] E = 460 × 1.60 × 10⁻¹⁹ (= 7.36 × 10⁻¹⁷ (J))
- [A1] v = [(2 × 460 × 1.60 × 10⁻¹⁹)/(9.11 × 10⁻³¹)]½ = 1.3 x 10⁷ ms⁻¹
- [M1] β⁻ particles have range of/different/various speeds/velocities/momenta/energies
- [A1] so they follow different paths
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