A student applies a potential difference V of (4.0 ± 0.1)V across a resistor of resistance R of (10.0 ± 0.3)Ω for a time t of (50 ± 1)s. The student calculates the energy E dissipated using the equation below. E = (V²t)/R = (4.0² × 50)/10.0 = 80 J What is the absolute uncertainty in the calculated energy value?
✓ Correct answer
D: 8 J
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