A beam of light consists of a continuous range of wavelengths from 420 nm to 740 nm. The light passes through a cloud of cool gas, as shown in Fig. 11.1. [Figure 11.1]
- (a)The spectrum of the light emerging from the cloud of cool gas is viewed using a diffraction grating. Explain why this spectrum contains a number of dark lines.[4]
- (b)(i)Light of wavelength 420 nm has a photon energy of 2.96 eV. Calculate the photon energy, in eV, of light of wavelength 740 nm.[2]
- (b)(ii)Use data from (i) and your answer in (i) to show, on Fig. 11.2, the changes in energy levels giving rise to the dark lines in (a). [Figure 11.2 (not to scale)][2]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (May/June 2017). The mark or mark type is shown in brackets.
- [B1] electrons (in gas atoms/molecules) interact with photons
- [B1] photon energy causes electron to move to higher energy level/to be excited
- [B1] photon energy = difference in energy of (electron) energy levels
- [B1] when electrons de-excite, photons emitted in all directions (so dark line)
- [C1] photon energy ∝ 1/λ
- [A1] energy = 1.68 eV
- [(C1)] or E = hc / λ
- [(C1)] E = 6.63 × 10⁻³⁴ × 3.0 × 10⁸ / (740 × 10⁻⁹)
- [(A1)] = 2.688 × 10⁻¹⁹ J
- [(A1)] energy = 1.68 eV
- [B2] 3.4 eV → 1.5 eV
- 3.4 eV → 0.85 eV
- 3.4 eV → 0.54 eV
- all correct and none incorrect 2/2
- 2 correct and 1 incorrect or only 2 correctly drawn 1/2
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