Define the ohm.
- (a)Define the ohm.[1]
- (b)A cell X of electromotive force (e.m.f.) 1.5V and negligible internal resistance is connected in series to three resistors A, B and C, as shown in Fig. 6.1. [Figure 6.1] Resistors A and B have resistances 6.0 Ω and 3.0 Ω respectively and are connected in parallel. Resistor C has resistance 4.0 Ω and is connected in series with the parallel combination. Calculate
- (b)(i)the current in the circuit,[3]
- (b)(ii)the current in resistor B,[1]
- (b)(iii)the ratio power dissipated in resistor B power dissipated in resistor C[2]
- (c)The resistors A, B and C in (b) are wires of the same material and have the same length.
- (c)(i)Explain how the resistors may be made with different resistance values.[1]
- (c)(ii)Calculate the ratio average drift speed of the charge carriers in resistor B average drift speed of the charge carriers in resistor C[2]
- (d)A cell of e.m.f. 1.5V and negligible internal resistance is connected in parallel with cell X in Fig. 6.1 with their positive terminals together. State the change, if any, to the current in
- (d)(i)cell X,[1]
- (d)(ii)resistor C.[1]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (May/June 2017). The mark or mark type is shown in brackets.
- [B1] volt / ampere
- [C1] R₁ = [1/3.0 + 1/6.0]⁻¹ + 4.0 (= 6.0 Ω)
- [C1] I = 1.5/6.0
- [A1] = 0.25 A
- [A1] VB = 0.5 V
- [A1] I = 0.5/3.0
- [A1] = 0.17 (0.167) A
- [C1] P = I²R or VI or V²/R
- [A1] ratio = (0.167² × 3.0) / (0.25² × 4.0)
- [A1] = 0.33
- [B1] vary/change/different radius/diameter/cross-sectional area (of wire)
- [C1] v = I / Ane
- [A1] ratio = (Ів / Ав) / (Ic / Ac)
- [A1] or (Ів Ас) / (Ic AB)
- [A1] (R x 1/A so) ratio = (IB RB) / (Ic Rc) = (0.167 x 3.0) / (0.25 x 4.0)
- [A1] = 0.50
- [A1] 0.25 A to 0.13 (0.125) A or halved
- [A1] no change
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