A-LevelPhysicsDynamics9702/12 · May/June 2017 · Q81 Mark
A golf ball of mass m is dropped onto a hard surface from a height h₁ and rebounds to a height h₂. The momentum of the golf ball just as it reaches the surface is different from its momentum just as it leaves the surface. What is the total change in the momentum of the golf ball between these two instants? (Ignore air resistance.)
Am√2gh₁ – m√2gh₂
Bm√2gh₁ + m√2gh₂
Cm√2g(h₁ – h₂)
Dm√2g(h₁ + h₂)
✓ Correct answer
B: m√2gh₁ + m√2gh₂
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