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A-LevelPhysicsD.C. circuits9702/22 · Feb/Mar 2021 · Q610 Marks

(b) A battery of electromotive force (e.m.f.) 12.0V and internal resistance r is connected to a filament lamp and a resistor, as shown in Fig. 6.1. [Figure 6.1] The current in the battery is 3.6A and the current in the resistor is 2.1A. The I-V characteristic for the lamp is shown in Fig. 6.2. [Figure 6.2]

  1. (a)State Kirchhoff's first law.[1]
  2. (b)(i)Determine the resistance of the lamp in Fig. 6.1. resistance = ..................................................... Ω[3]
  3. (b)(ii)Determine the internal resistance r of the battery. r = ..................................................... Ω[2]
  4. (b)(iii)The initial energy stored in the battery is 470kJ. Assume that the e.m.f. and the current in the battery do not change with time. Calculate the time taken for the energy stored in the battery to become 240 kJ. time = ..................................................... s[2]
  5. (b)(iv)The filament wire of the lamp is connected in series with the adjacent copper connecting wire of the circuit, as illustrated in Fig. 6.3. [Figure 6.3] Some data for the filament wire and the adjacent copper connecting wire are given in Table 6.1. Table 6.1 filament wire copper wire cross-sectional area A 360 A number density of free electrons n 2.5 n Calculate the ratio average drift speed of free electrons in filament wire average drift speed of free electrons in copper wire ratio = .....................................................[2]

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Mark scheme

Marking points from the official mark scheme (Feb/Mar 2021). The mark or mark type is shown in brackets.

  1. [B1] (a) sum of current(s) into junction = sum of current(s) out of junction or (algebraic) sum of current(s) at a junction is zero
  2. [C1] (b)(i) I = 3.6-2.1 = 1.5
  3. [C1] (b)(i) V= 4.4
  4. [A1] (b)(i) R= 4.4/1.5 = 2.9 Ω
  5. [C1] (b)(ii) 12.0 = 4.4 + 3.6r or 12.0 = 3.6 (1.2 + r)
  6. [A1] (b)(ii) r = 2.1 Ω
  7. [C1] (b)(iii) t = (470 × 103 – 240 × 103 ) / (12 × 3.6)
  8. [A1] (b)(iii) = 5300 s
  9. [C1] (b)(iv) I = Anvq
  10. [A1] (b)(iv) ratio = (360A / A) × (2.5n / n) or 360 × 2.5 = 900

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About this question

Topic
D.C. circuits, A-Level Physics (syllabus 9702). Structured question, 10 marks.
Source
A-Level Physics, Feb/Mar 2021 Paper 2 Variant 2, question 6.

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