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A-LevelPhysicsElectric fields9702/42 · Feb/Mar 2020 · Q68 Marks

6 Two positively charged identical metal spheres A and B have their centres separated by a distance of 24 cm, as shown in Fig. 6.1. [Figure 6.1] The variation with distance x from the centre of A of the electric field strength E due to the two spheres, along the line joining their centres, is represented in Fig. 6.2. [Figure 6.2]

  1. (a)State the radius of the two spheres. radius = ................................................................ cm [1][1]
  2. (b)The charge on sphere A is 3.6 × 10⁻⁹C. Determine the charge Q_B on sphere B. Assume that spheres A and B can be treated as point charges at their centres. Explain your working. Q_B = ........................................................................ C [3][3]
  3. (c)(i)Sphere B is removed. Use information from (b) to determine the electric potential on the surface of sphere A. electric potential = ................................................................ V [2][2]
  4. (c)(ii)Calculate the capacitance of sphere A. capacitance = ................................................................ F [2][2]

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Mark scheme

Marking points from the official mark scheme (Feb/Mar 2020). The mark or mark type is shown in brackets.

  1. [1] 2.0 cm
  2. [1] At 16 (cm) from A the electric fields are equal or E_A = E_B
  3. [1] E = Q / 4πε₀r²
  4. [1] Q_B = 9.0 × 10⁻¹⁰ C
  5. [1] V = Q / 4πε₀r_A
  6. [1] V = 3.6 × 10⁻⁹ / (4 × π × 8.85 × 10⁻¹² × 0.020) = 1600 V
  7. [1] C = Q / V
  8. [1] = 3.6 × 10⁻⁹ / 1600 = 2.3 × 10⁻¹² F

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About this question

Topic
Electric fields, A-Level Physics (syllabus 9702). Structured question, 8 marks.
Source
A-Level Physics, Feb/Mar 2020 Paper 4 Variant 2, question 6.

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