Some glass lenses are converging lenses, and others are diverging lenses.
- (a)Draw the cross-section of a diverging lens.[1]
- (b)(i)Fig. 5.1 shows the cross-section of a converging lens, the principal axis and the two principal focuses (focal points) F₁ and F₂ on a full-scale grid. [Figure 5.1] A student places an object of height 2.1 cm at a distance of 3.0 cm from the centre of the lens. Using Fig. 5.1, determine the focal length of the lens. focal length = ........................................................... cm[1]
- (b)(ii)On Fig. 5.1, draw a vertical arrow of height 2.1 cm that is 3.0 cm from the centre of the lens and label the arrow O. The arrow is the object.[1]
- (b)(iii)On Fig. 5.1, draw two rays from the tip of the object arrow to find the tip of the image. Draw another arrow to show the image.[3]
- (b)(iv)Using the image marked on Fig. 5.1 in (b)(iii), determine the linear magnification produced. magnification = ........................................................[2]
- (b)(v)Explain whether the image of the object is real or virtual.[1]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2024). The mark or mark type is shown in brackets.
- [1] a drawn lens that is thinner at the middle (than at the edges)
- [1] 1.8 (cm)
- [1] vertical arrow of height 2.1 cm drawn 3.0 cm from lens (and labelled O)
- [2] any two from: paraxial ray from tip of object to lens that then refracts through F₂; ray from tip of object, straight through and past optical centre; ray from tip of object through F₁ to lens that then emerges paraxially
- [1] image drawn from (sensible) intersection to principal axis
- [1] (linear magnification =) hᵢ / hₒ or height of candidate's image / 2.1 (cm)
- [1] 1.2 < magnification < 1.8
- [1] real and formed by converging light / rays
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