A plane, irregular lamina has a mass of 50 g. It hangs from a nail that passes through a small hole H near to the edge of the lamina. The nail acts as a pivot and the lamina can swing about it. The lamina is held in the position shown in Fig. 3.1, a small distance above a horizontal bench. [Figure 3.1] The centre of gravity of the lamina is at G.
- (a)(i)The weight of the lamina is a force that acts downwards. Explain why the lamina experiences this downward force.[1]
- (a)(ii)Calculate the weight of the lamina on Earth. weight = .......................... N[2]
- (b)(i)The weight produces a moment about the pivot through H. Using Fig. 3.1, calculate the moment of the weight about the pivot. moment = .......................... N m[2]
- (b)(ii)The lamina is now released from the position shown in Fig. 3.1. Describe what happens to the lamina from the time it is released until it stops moving.[3]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2023). The mark or mark type is shown in brackets.
- [1] it / lamina is in the gravitational field (of Earth)
- [1] (F =) mg or 0.050 × 9.8 or 50 × 9.8 or 490
- [1] 0.49 (N)
- [1] (M =) F × x⊥ or 0.49 × 8.0 or 0.49 × 0.080
- [1] 0.039 (N m)
- [1] it / lamina moves clockwise (about the pivot)
- [1] it speeds up and then slows down or it oscillates (with decreasing amplitude) or overshoots
- [1] (stops with) G vertically below H
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