Skip to main content
A-LevelPhysicsCapacitance9702/51 · Oct/Nov 2021 · Q215 Marks

A student investigates the discharge of a capacitor in the circuit shown in Fig. 2.1. E C V R1 R2 P Q Fig. 2.1 The student closes the switch and charges the capacitor. The switch is opened and a stop-watch is started. The capacitor discharges through the two resistors of resistance R₁ and R₂ connected between P and Q. At a fixed time t the potential difference V across the capacitor is measured. The experiment is repeated for different values of R₁ and R₂. It is suggested that V, R₁ and R₂ are related by the equation V t In( ) = - E C(R₁ + R₂) where E is the electromotive force (e.m.f.) of the battery and C is the capacitance of the capacitor.

  1. (a)A graph is plotted of In V on the y-axis against 1/(R₁ + R₂) on the x-axis. Determine expressions for the gradient and y-intercept. gradient = y-intercept =[2]
  2. (b)Values of R₁, R₂, V and In V are given in Table 2.1. Each resistance value has a percentage uncertainty of ±5%. Table 2.1 R₁/ΚΩ R2/ΚΩ (R1 + R2)/ΚΩ 1/(R1 + R2)/10⁻⁶Ω⁻¹ V/V In (V/V) 22 33 1.28 0.247 22 47 1.98 0.683 22 68 2.87 1.054 33 47 2.39 0.871 33 68 3.28 1.188 47 68 3.55 1.267 Calculate and record values of (R₁ + R₂)/kΩ and 1/(R₁ + R₂)/10⁻⁶ Ω⁻¹ in Table 2.1. Include the absolute uncertainties in (R₁ + R₂) and 1/(R₁ + R₂).[2]
  3. (c)(i)Plot a graph of In (V/V) against 1/(R₁ + R₂)/10⁻⁶ Ω⁻¹. Include error bars for 1/(R₁ + R₂).[2]
  4. (c)(ii)Draw the straight line of best fit and a worst acceptable straight line on your graph. Both lines should be clearly labelled.[2]
  5. (c)(iii)Determine the gradient of the line of best fit. Include the absolute uncertainty in your answer. gradient =[2]
  6. (c)(iv)Determine the y-intercept of the line of best fit. Include the absolute uncertainty in your answer. y-intercept =[2]
  7. (d)(i)Using your answers to (a), (c)(iii) and (c)(iv), determine the values of C and E. Include appropriate units. Data: t = (60 ± 1)s C = E =[2]
  8. (d)(ii)Determine the percentage uncertainty in C. percentage uncertainty =[1]
  9. (e)The experiment is repeated using the same capacitor. Determine the value of (R₁ + R₂) that would give a value of V of 5.0V at time t = 60s. (R₁ + R₂) =[1]

This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.

Mark scheme

Marking points from the official mark scheme (Oct/Nov 2021). The mark or mark type is shown in brackets.

  1. [1] gradient = -t/C
  2. [1] y-intercept = In E
  3. [1] Values of (R₁ + R₂)/kΩ and 1/(R₁ + R₂)/10⁻⁶Ω⁻¹ correct as shown below: (R₁+R₂)/kΩ: 55 (±3), 1/(R₁+R₂)/10⁻⁶Ω⁻¹: 18 or 18.2 ± 0.9 (R₁+R₂)/kΩ: 69 (± 3 or 4), 1/(R₁+R₂)/10⁻⁶Ω⁻¹: 14 or 14.5 ± 0.7 (R₁+R₂)/kΩ: 90 (± 4 or 5), 1/(R₁+R₂)/10⁻⁶Ω⁻¹: 11 or 11.1 ± 0.6 (R₁+R₂)/kΩ: 80 (±4), 1/(R₁+R₂)/10⁻⁶Ω⁻¹: 13 or 12.5 ± 0.6 (R₁+R₂)/kΩ: 101 (±5), 1/(R₁+R₂)/10⁻⁶Ω⁻¹: 9.9 or 9.90 or 9.901 ± 0.5 (R₁+R₂)/kΩ: 115 (±6), 1/(R₁+R₂)/10⁻⁶Ω⁻¹: 8.7 or 8.70 or 8.696 ± 0.4
  4. [1] Absolute uncertainties in 1/(R₁ + R₂) from ± 0.9 or ± 1 to ± 0.4 or ± 0.5.
  5. [1] Six points plotted correctly. Must be accurate to half a small square. Diameter of points must be less than half a small square.
  6. [1] Error bars in 1/(R₁ + R₂) plotted correctly. All error bars must be plotted. Total length of bar must be accurate to less than half a small square and symmetrical.
  7. [1] Line of best fit drawn. Points must be balanced. Do not accept line from top point to bottom point. Line must pass between (10.2, 1.10) and (10.8, 1.10) and between (16.7, 0.40) and (17.2, 0.40).
  8. [1] Worst acceptable line drawn (steepest or shallowest possible line that passes through all error bars). All error bars must be plotted.
  9. [1] Negative gradient determined with clear substitution of data points into Δy/Δx. Distance between data points must be at least half the length of the drawn line.
  10. [1] Gradient of worst acceptable line determined. uncertainty = (gradient of line of best fit – gradient of worst acceptable line) or uncertainty = ½ (steepest worst line gradient – shallowest worst line gradient)
  11. [1] y-intercept determined by substitution of point on line into y = mx + c.
  12. [1] y-intercept of worst acceptable line determined by substitution of point on line into y = mx + c. uncertainty = y-intercept of line of best fit – y-intercept of worst acceptable line or uncertainty = ½ (steepest worst line y-intercept – shallowest worst line y-intercept) Do not accept ECF from false origin method.
  13. [1] C determined using gradient and C and E both given to two or three significant figures. C = -t/gradient = 60/(c)(iii)
  14. [1] E determined using y-intercept and C and E both given with correct SI unit. E = e^(y-intercept) unit of C: F or CV⁻¹ or sΩ⁻¹ unit of E: V
  15. [1] Percentage uncertainty determined with method shown. percentage uncertainty = (|Δt/t| + |Δgradient/gradient|) × 100 Clear substitution must be shown for maximum/minimum methods.
  16. [1] (R₁ + R₂) determined to at least two significant figures from (d)(i) or (c)(iii) and (c)(iv) with correct substitution including signs and correct power of ten(s). Do not accept ECF for POT from (c)(iii), (c)(iv) or (d). (R₁+R₂) = -t/C × 1/(In V - In E) = -60/C × 1/(In 5.0 - In E) or (R₁+R₂) = gradient / (In 5.0 - y-intercept) = (c)(iii) / (1.61 - (c)(iv))

Write your answer and get it marked

On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.

Sign up free →

About this question

Topic
Capacitance, A-Level Physics (syllabus 9702). Structured question, 15 marks.
Source
A-Level Physics, Oct/Nov 2021 Paper 5 Variant 1, question 2.

Questions and mark schemes are from past examination papers and remain the copyright of the exam board. How Oracle Prep builds its content

Related Physics questions

© 2026 Oracle Prep