(a) State what is meant by the centre of gravity of a body. (b) A uniform wooden post AB of weight 45N stands in equilibrium on hard ground, as shown in Fig. 2.1. [Figure 2.1] End A of the vertical post is supported by the ground. A horizontal wire with tension T is attached to end B of the post. Another wire, attached to the post at point C, is at an angle of 60° to the horizontal and has tension 38 N. The distances along the post of points A, B and C are shown in Fig. 2.1.
- (a)State what is meant by the centre of gravity of a body. [2][2]
- (b)(i)Calculate the horizontal component of the force exerted on the post by the wire connected to point C. horizontal component of force = ..................................................... N [1][1]
- (b)(ii)By considering moments about end A, determine the tension T. T = ............................................................................................ N [2][2]
- (b)(iii)Calculate the vertical component of the force exerted on the post at end A. force = ..................................................................................... N [1][1]
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Mark scheme
Marking points from the official mark scheme (Oct/Nov 2020). The mark or mark type is shown in brackets.
- [1] point where (all) the weight (of the body)
- [1] is considered/seems to act
- [1] horizontal component of force = 38 cos 60° or 38 sin 30°
- [1] = 19 N
- [1] (T × 1.2) or (19 × 0.9) or 17
- [1] (T × 1.2) = (19 × 0.9)
- [1] T = 14 N
- [1] F = 45 + 38 sin 60°
- [1] = 78 N
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