what is seen through the microscope
- (a)(i)what is seen through the microscope[1]
- (a)(ii)how Brownian motion provides evidence for the nature of the movement of gas molecules.[2]
- (b)(i)the amount, in mol, of the gas amount = ..................................................... mol [3][3]
- (b)(ii)the thermal energy transfer during the change. energy transfer = ..................................................... J [2][2]
- (c)(i)the quantity of external work done on the gas work done = ..................................................... J [1][1]
- (c)(ii)the change in internal energy, with the direction of this change. change = ..................................................... J direction ..................................................... [2][2]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2019). The mark or mark type is shown in brackets.
- [B1] specks of light moving haphazardly
- [M1] (gas) molecules collide with (smoke) particles / random motion of the (gas) molecules
- [A1] causes the (haphazard) motion of the smoke particles / causes the smoke particles to change direction
- [C1] pV = nRT
- [C1] n = (3.51 × 10⁵ × 2.40 × 10⁻³) / (8.31 × 290) or n = (3.75 × 10⁵ × 2.40 × 10⁻³) / (8.31 × 310) or pV = NkT (C1) n = (3.51 × 10⁵ × 2.40 × 10⁻³) / (1.38 × 10⁻²³ × 6.02 × 10²³ × 290) or n = (3.75 × 10⁵ × 2.40 × 10⁻³) / (1.38 × 10⁻²³ × 6.02 × 10²³ × 310)
- [A1] n = 0.350 mol or 0.349 mol
- [C1] energy transfer = (0.349 or 0.35) × 12.5 × (310 – 290)
- [A1] = 87.3 J or 87.5 J
- [A1] zero
- [A1] 87.3 J or 87.5 J
- [B1] increase
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