With reference to the photoelectric effect, state what is meant by work function energy.
- (a)With reference to the photoelectric effect, state what is meant by work function energy.[2]
- (b)(i)The work function energy of a clean metal surface is 5.5 × 10⁻¹⁹J. Electromagnetic radiation of wavelength 280 nm is incident on the metal surface. The metal is in a vacuum. Calculate: 1. the photon energy photon energy = ........................................................... J[2]
- (b)(i) 2.the maximum speed V_MAX of the electrons emitted from the surface. V_MAX = ........................................................... ms⁻¹[3]
- (b)(ii)Explain why most of the emitted electrons will have a speed lower than V_MAX[1]
- (c)The electromagnetic radiation incident on the metal surface may change in intensity or in frequency. Complete [Figure 11.1] by inserting either 'increases' or 'decreases' or 'no change' to describe the effects of the changes shown on the maximum speed and on the rate of emission of electrons.[4]
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Mark scheme
Marking points from the official mark scheme (Oct/Nov 2019). The mark or mark type is shown in brackets.
- [M1] energy (of photon) required to remove electron
- [A1] from a surface
- [A1] or reference to minimum energy
- [A1] or reference to zero kinetic energy
- [C1] photon energy = hc / λ
- [C1] = (6.63 × 10-34 × 3.00 × 108) / (280 × 10-9)
- [A1] = 7.1 x 10-19 J
- [C1] electron energy = (7.1-5.5) × 10-19 J
- [C1] ½ x 9.11 x 10-31 x v² = (7.1 – 5.5) × 10-19
- [A1] v = 5.9 x 105 m s-1
- [B1] energy is required to bring electron to the surface
- [B1] no change
- [B1] decreases
- [B1] decreases
- [B1] decreases
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