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A-LevelPhysicsQuantum physics9702/41 · Oct/Nov 2019 · Q1112 Marks

With reference to the photoelectric effect, state what is meant by work function energy.

  1. (a)With reference to the photoelectric effect, state what is meant by work function energy.[2]
  2. (b)(i)The work function energy of a clean metal surface is 5.5 × 10⁻¹⁹J. Electromagnetic radiation of wavelength 280 nm is incident on the metal surface. The metal is in a vacuum. Calculate: 1. the photon energy photon energy = ........................................................... J[2]
  3. (b)(i) 2.the maximum speed V_MAX of the electrons emitted from the surface. V_MAX = ........................................................... ms⁻¹[3]
  4. (b)(ii)Explain why most of the emitted electrons will have a speed lower than V_MAX[1]
  5. (c)The electromagnetic radiation incident on the metal surface may change in intensity or in frequency. Complete [Figure 11.1] by inserting either 'increases' or 'decreases' or 'no change' to describe the effects of the changes shown on the maximum speed and on the rate of emission of electrons.[4]

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Mark scheme

Marking points from the official mark scheme (Oct/Nov 2019). The mark or mark type is shown in brackets.

  1. [M1] energy (of photon) required to remove electron
  2. [A1] from a surface
  3. [A1] or reference to minimum energy
  4. [A1] or reference to zero kinetic energy
  5. [C1] photon energy = hc / λ
  6. [C1] = (6.63 × 10-34 × 3.00 × 108) / (280 × 10-9)
  7. [A1] = 7.1 x 10-19 J
  8. [C1] electron energy = (7.1-5.5) × 10-19 J
  9. [C1] ½ x 9.11 x 10-31 x v² = (7.1 – 5.5) × 10-19
  10. [A1] v = 5.9 x 105 m s-1
  11. [B1] energy is required to bring electron to the surface
  12. [B1] no change
  13. [B1] decreases
  14. [B1] decreases
  15. [B1] decreases

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About this question

Topic
Quantum physics, A-Level Physics (syllabus 9702). Structured question, 12 marks.
Source
A-Level Physics, Oct/Nov 2019 Paper 4 Variant 1, question 11.

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