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A-LevelPhysicsDynamics9702/22 · Oct/Nov 2019 · Q314 Marks

State Newton's third law of motion.

  1. (a)State Newton's third law of motion.[2]
  2. (b)A block X of mass mx slides in a straight line along a horizontal frictionless surface, as shown in Fig. 3.1. [Figure 3.1] The block X, moving with speed 5v, collides head-on with a stationary block Y of mass mү. The two blocks stick together and then move with common speed v, as shown in Fig. 3.2. [Figure 3.2]
  3. (b)(i)Use conservation of momentum to show that the ratio mү / mx is equal to 4.[2]
  4. (b)(ii)Calculate the ratio total kinetic energy of X and Y after collision / total kinetic energy of X and Y before collision ratio =[3]
  5. (b)(iii)State the value of the ratio in (ii) for a perfectly elastic collision. ratio[1]
  6. (c)The variation with time t of the momentum of block X in (b) is shown in Fig. 3.3. [Figure 3.3] Block X makes contact with block Y at time t = 20 ms.
  7. (c)(i)Describe, qualitatively, the magnitude and direction of the resultant force, if any, acting on block X in the time interval: 1. t = 0 to t = 20 ms 2. t = 20 ms to t = 40 ms.[3]
  8. (c)(ii)On Fig. 3.3, sketch the variation of the momentum of block Y with time t from t = 0 to t = 60 ms.[3]

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Mark scheme

Marking points from the official mark scheme (Oct/Nov 2019). The mark or mark type is shown in brackets.

  1. [B1] force on body A (by body B) is equal (in magnitude) to force on body B (by body A)
  2. [B1] force on body A (by body B) is opposite (in direction) to force on body B (by body A)
  3. [C1] mxx5v or (mx + my) x v
  4. [A1] mx x 5v = (mx + my) x v (so) my / mx = 4
  5. [C1] (E =) 1/2mv²
  6. [C1] ratio = [1/2 x (mx + my) x v²] / [1/2 × mx × (5v)²]
  7. [A1] = 0.2
  8. [A1] ratio = 1
  9. [B1] 1. (magnitude of resultant force is) zero
  10. [B1] 2. (magnitude of resultant force is) constant
  11. [B1] (direction of resultant force is) opposite to the momentum
  12. [B1] horizontal line from (0 ms, 0 squares) ending at (20 ms, 0 squares)
  13. [B1] straight line from (20 ms, 0 squares) ending at (40 ms, 4.0 squares [= 4.0 cm vertically])
  14. [B1] horizontal line from (40 ms, 4.0 squares) ending at (60 ms, 4.0 squares)

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About this question

Topic
Dynamics, A-Level Physics (syllabus 9702). Structured question, 14 marks.
Source
A-Level Physics, Oct/Nov 2019 Paper 2 Variant 2, question 3.

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