State Newton's third law of motion.
- (a)State Newton's third law of motion.[2]
- (b)A block X of mass mx slides in a straight line along a horizontal frictionless surface, as shown in Fig. 3.1. [Figure 3.1] The block X, moving with speed 5v, collides head-on with a stationary block Y of mass mү. The two blocks stick together and then move with common speed v, as shown in Fig. 3.2. [Figure 3.2]
- (b)(i)Use conservation of momentum to show that the ratio mү / mx is equal to 4.[2]
- (b)(ii)Calculate the ratio total kinetic energy of X and Y after collision / total kinetic energy of X and Y before collision ratio =[3]
- (b)(iii)State the value of the ratio in (ii) for a perfectly elastic collision. ratio[1]
- (c)The variation with time t of the momentum of block X in (b) is shown in Fig. 3.3. [Figure 3.3] Block X makes contact with block Y at time t = 20 ms.
- (c)(i)Describe, qualitatively, the magnitude and direction of the resultant force, if any, acting on block X in the time interval: 1. t = 0 to t = 20 ms 2. t = 20 ms to t = 40 ms.[3]
- (c)(ii)On Fig. 3.3, sketch the variation of the momentum of block Y with time t from t = 0 to t = 60 ms.[3]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2019). The mark or mark type is shown in brackets.
- [B1] force on body A (by body B) is equal (in magnitude) to force on body B (by body A)
- [B1] force on body A (by body B) is opposite (in direction) to force on body B (by body A)
- [C1] mxx5v or (mx + my) x v
- [A1] mx x 5v = (mx + my) x v (so) my / mx = 4
- [C1] (E =) 1/2mv²
- [C1] ratio = [1/2 x (mx + my) x v²] / [1/2 × mx × (5v)²]
- [A1] = 0.2
- [A1] ratio = 1
- [B1] 1. (magnitude of resultant force is) zero
- [B1] 2. (magnitude of resultant force is) constant
- [B1] (direction of resultant force is) opposite to the momentum
- [B1] horizontal line from (0 ms, 0 squares) ending at (20 ms, 0 squares)
- [B1] straight line from (20 ms, 0 squares) ending at (40 ms, 4.0 squares [= 4.0 cm vertically])
- [B1] horizontal line from (40 ms, 4.0 squares) ending at (60 ms, 4.0 squares)
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →