Define power.
- (a)(i)Define power.[1]
- (a)(ii)State what is meant by gravitational potential energy.[1]
- (b)An aircraft of mass 1200kg climbs upwards with a constant velocity of 45ms⁻¹, as shown in Fig. 3.1. [Figure 3.1] (not to scale) The aircraft's engine produces a thrust force of 2.0 × 10³N to move the aircraft through the air. The rate of increase in height of the aircraft is 3.3ms⁻¹.
- (b)(i)Calculate the power produced by the thrust force.[2]
- (b)(ii)1.Determine, for a time interval of 3.0 minutes, the work done by the thrust force to move the aircraft,[2]
- (b)(ii)2.Determine, for a time interval of 3.0 minutes, the increase in gravitational potential energy of the aircraft,[2]
- (b)(ii)3.Determine, for a time interval of 3.0 minutes, the work done against air resistance.[1]
- (b)(iii)Use your answer in (b)(ii) part 3 to calculate the force due to air resistance acting on the aircraft.[1]
- (b)(iv)With reference to the motion of the aircraft, state and explain whether the aircraft is in equilibrium.[2]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2018). The mark or mark type is shown in brackets.
- [1] work (done)/time (taken)
- [1] energy of a mass due to its position in a gravitational field
- [2] P = Fv
- [2] = 2.0 x 10³ x 45
- [2] = 9.0 × 10⁴ W
- [2] W = (2.0 × 10³) × (45 x 3.0 × 60) or W = 9.0 × 10⁴ × 3.0 × 60
- [2] W = 1.6 x 10⁷ J
- [2] (Δ)ΕΡ = mg(△)h
- [2] = 1200 × 9.81 x 3.3 × 3.0 × 60
- [2] = 7.0 × 10⁶ J
- [1] W = 1.6 × 10⁷ – 7.0 × 10⁶
- [1] = 9.0 × 10⁶ J
- [1] force = (9.0 × 10⁶)/(45 × 3.0 × 60)
- [1] = 1.1 x 10³ N
- [2] constant velocity so no resultant force
- [2] no resultant force so in equilibrium
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →