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A-LevelPhysicsWork, energy and power9702/21 · Oct/Nov 2018 · Q312 Marks

Define power.

  1. (a)(i)Define power.[1]
  2. (a)(ii)State what is meant by gravitational potential energy.[1]
  3. (b)An aircraft of mass 1200kg climbs upwards with a constant velocity of 45ms⁻¹, as shown in Fig. 3.1. [Figure 3.1] (not to scale) The aircraft's engine produces a thrust force of 2.0 × 10³N to move the aircraft through the air. The rate of increase in height of the aircraft is 3.3ms⁻¹.
  4. (b)(i)Calculate the power produced by the thrust force.[2]
  5. (b)(ii)1.Determine, for a time interval of 3.0 minutes, the work done by the thrust force to move the aircraft,[2]
  6. (b)(ii)2.Determine, for a time interval of 3.0 minutes, the increase in gravitational potential energy of the aircraft,[2]
  7. (b)(ii)3.Determine, for a time interval of 3.0 minutes, the work done against air resistance.[1]
  8. (b)(iii)Use your answer in (b)(ii) part 3 to calculate the force due to air resistance acting on the aircraft.[1]
  9. (b)(iv)With reference to the motion of the aircraft, state and explain whether the aircraft is in equilibrium.[2]

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Mark scheme

Marking points from the official mark scheme (Oct/Nov 2018). The mark or mark type is shown in brackets.

  1. [1] work (done)/time (taken)
  2. [1] energy of a mass due to its position in a gravitational field
  3. [2] P = Fv
  4. [2] = 2.0 x 10³ x 45
  5. [2] = 9.0 × 10⁴ W
  6. [2] W = (2.0 × 10³) × (45 x 3.0 × 60) or W = 9.0 × 10⁴ × 3.0 × 60
  7. [2] W = 1.6 x 10⁷ J
  8. [2] (Δ)ΕΡ = mg(△)h
  9. [2] = 1200 × 9.81 x 3.3 × 3.0 × 60
  10. [2] = 7.0 × 10⁶ J
  11. [1] W = 1.6 × 10⁷ – 7.0 × 10⁶
  12. [1] = 9.0 × 10⁶ J
  13. [1] force = (9.0 × 10⁶)/(45 × 3.0 × 60)
  14. [1] = 1.1 x 10³ N
  15. [2] constant velocity so no resultant force
  16. [2] no resultant force so in equilibrium

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About this question

Topic
Work, energy and power, A-Level Physics (syllabus 9702). Structured question, 12 marks.
Source
A-Level Physics, Oct/Nov 2018 Paper 2 Variant 1, question 3.

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