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A-LevelPhysicsElectric fields9702/42 · Oct/Nov 2017 · Q67 Marks

(b) An isolated spherical conductor has charge q, as shown in Fig. 6.1. [Figure 6.1] Point P is a movable point that, at any one time, is a distance x from the centre of the sphere. The variation with distance x of the electric potential V at point P due to the charge on the sphere is shown in Fig. 6.2. [Figure 6.2] Use Fig. 6.2 to determine

  1. (a)For any point outside a spherical conductor, the charge on the sphere may be considered to act as a point charge at its centre. By reference to electric field lines, explain this.[2]
  2. (b)(i)the electric field strength E at point P where x = 6.0 cm, E = .............................. N C⁻¹[3]
  3. (b)(ii)the radius R of the sphere. Explain your answer. R = .............................. cm[2]

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Mark scheme

Marking points from the official mark scheme (Oct/Nov 2017). The mark or mark type is shown in brackets.

  1. [1] (a) electric field lines are radial/normal to surface (of sphere)
  2. [1] (a) electric field lines appear to originate from centre (of sphere)
  3. [1] (b)(i) tangent drawn at x = 6.0cm and gradient calculation attempted
  4. [2] (b)(i) E = 9.0 × 10⁴ NC⁻¹ (1 mark if in range ±1.2; 2 marks if in range ±0.6)
  5. [1] (b)(i) or correct pair of values of V and x read from curved part of graph and substituted into V = q/4πεx
  6. [1] (b)(i) to give q = 3.6 × 10⁻⁸C
  7. [1] (b)(i) (then E = q/4πεx² and x = 6cm gives) E = 9.0 × 10⁴ NC⁻¹
  8. [1] (b)(i) or (E = q/4πεx² and V = q / 4πεx and so) E = V/x
  9. [1] (b)(i) giving E = 5.4 × 10³/0.060
  10. [1] (b)(i) = 9.0 × 10⁴ NC⁻¹
  11. [1] (b)(ii) (R =) 2.5 cm
  12. [1] (b)(ii) potential inside a conductor is constant or field strength inside a conductor zero (so gradient is zero)

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About this question

Topic
Electric fields, A-Level Physics (syllabus 9702). Structured question, 7 marks.
Source
A-Level Physics, Oct/Nov 2017 Paper 4 Variant 2, question 6.

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