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A-LevelPhysicsMagnetic fields9702/41 · Oct/Nov 2017 · Q88 Marks

A thin slice of conducting material is placed normal to a uniform magnetic field of flux density B, as shown in Fig. 8.1. [Figure 8.1] The magnetic field is normal to face CDEF and to face PQRS. A current I passes through the slice and is normal to the faces CDQP and FERS. A potential difference, the Hall voltage V_H, is developed across the slice.

  1. (a)State the faces between which the Hall voltage V_H is developed.[1]
  2. (b)(i)The current I is produced by charge carriers, each of charge +q moving at speed v in the direction of the current. The number density of the charge carriers is n. Derive an expression relating the Hall voltage V_H to v, B and d, where d is one of the dimensions of the slice.[3]
  3. (b)(ii)Use your answer in (b)(i) and an expression for the current I in the slice to derive the expression V_H = BI / ntq. Explain your working.[2]
  4. (c)Suggest why the Hall voltage is difficult to detect in a thin slice of copper.[2]

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Mark scheme

Marking points from the official mark scheme (Oct/Nov 2017). The mark or mark type is shown in brackets.

  1. [B1] DERQ and CFSP
  2. [B1] force (on charge) due to magnetic field = force due to electric field
  3. [B1] Bqv = Eq
  4. [B1] v = E/B
  5. [B1] E = VH/d
  6. [B1] VH = Bvd
  7. [M1] use of I = nAqv and A = dt
  8. [A1] algebra clear leading to VH = BI/ntq
  9. [M1] (in metal,) n is very large
  10. [A1] (therefore) VH is small

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About this question

Topic
Magnetic fields, A-Level Physics (syllabus 9702). Structured question, 8 marks.
Source
A-Level Physics, Oct/Nov 2017 Paper 4 Variant 1, question 8.

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