Two capacitors P and Q, each of capacitance C, are connected in series with a battery of e.m.f. 9.0 V, as shown in Fig. 6.1. [Figure 6.1] A switch S is used to connect either a third capacitor T, also of capacitance C, or a resistor R, in parallel with capacitor P.
- (a)(i)Switch S is in position X. Calculate the combined capacitance, in terms of C, of the three capacitors,[2]
- (a)(ii)the potential difference across capacitor Q. Explain your working.[2]
- (b)Switch S is now moved to position Y. State what happens to the potential difference across capacitor P and across capacitor Q.[4]
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Mark scheme
Marking points from the official mark scheme (Oct/Nov 2017). The mark or mark type is shown in brackets.
- [C1] 1/T = 1/(2C) + 1/C
- [A1] T = ⅔C or 0.67C
- [B1] same charge on Q as on combination
- [B1] so p.d. is 6.0 V
- [B1] P: p.d. will decrease (from 3.0V)
- [B1] to zero
- [B1] Q: p.d. will increase (from 6.0V)
- [B1] to 9.0V
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