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A-LevelPhysicsD.C. circuits9702/12 · May/June 2022 · Q371 Mark

A potentiometer circuit is used to determine the electromotive force (e.m.f.) Eₓ of a cell. The circuit includes a second cell of known e.m.f. E₀ and negligible internal resistance, and a uniform resistance wire PQ of known length. Eₓ is less than E₀. The movable connection J can be positioned anywhere along the length of the resistance wire. Which circuit is suitable for determining Eₓ?

This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.

A[Circuit diagram with E₀ driving potentiometer wire (positive left), Eₓ connected to P (positive) and J via galvanometer (negative)]
B[Circuit diagram with E₀ driving potentiometer wire (positive left), Eₓ connected to P (negative) and J via galvanometer (positive)]
C[Circuit diagram with Eₓ driving potentiometer wire (positive left), E₀ connected to P (positive) and J via galvanometer (negative)]
D[Circuit diagram with E₀ driving potentiometer wire (positive left), Eₓ connected to P (negative) and J via galvanometer (positive)]

✓ Correct answer

D: [Circuit diagram with E₀ driving potentiometer wire (positive left), Eₓ connected to P (negative) and J via galvanometer (positive)]

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About this question

Topic
D.C. circuits, A-Level Physics (syllabus 9702). Multiple choice, 1 mark.
Source
A-Level Physics, May/June 2022 Paper 1 Variant 2, question 37.

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