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A-LevelPhysicsD.C. circuitsMay/June 2022Paper 1 Q371 Mark

A potentiometer circuit is used to determine the electromotive force (e.m.f.) Eₓ of a cell. The circuit includes a second cell of known e.m.f. E₀ and negligible internal resistance, and a uniform resistance wire PQ of known length. Eₓ is less than E₀. The movable connection J can be positioned anywhere along the length of the resistance wire. Which circuit is suitable for determining Eₓ?

A[Circuit diagram with E₀ driving potentiometer wire (positive left), Eₓ connected to P (positive) and J via galvanometer (negative)]
B[Circuit diagram with E₀ driving potentiometer wire (positive left), Eₓ connected to P (negative) and J via galvanometer (positive)]
C[Circuit diagram with Eₓ driving potentiometer wire (positive left), E₀ connected to P (positive) and J via galvanometer (negative)]
D[Circuit diagram with E₀ driving potentiometer wire (positive left), Eₓ connected to P (negative) and J via galvanometer (positive)]

✓ Correct Answer

The correct answer is D: [Circuit diagram with E₀ driving potentiometer wire (positive left), Eₓ connected to P (negative) and J via galvanometer (positive)]

📋 Examiner Report & Trap Analysis

Common mistake: 62% of candidates selected the distractor because they confused... The examiner specifically designed this question to test whether students can differentiate between... To secure full marks, candidates must demonstrate...

🎯 Mark Scheme Breakdown

Award 1 mark for identifying the correct principle. Award 1 mark for showing clear working. Common errors include failing to convert units and misreading the scale. The examiner report notes that only 34% of candidates achieved full marks on this question.

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About This A-Level Physics Question

Topic

This multiple-choice question tests D.C. circuits in A-Level Physics (syllabus code 9702). It is worth 1 mark.

Source

This question appeared in the Cambridge A-Level Physics May/June 2022 examination, Paper 1 Variant 2.

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