An elastic cord of unstretched total length 16.0 cm and cross-sectional area 2.0 × 10⁻⁶ m² is held horizontally by two smooth pins a distance 8.0 cm apart. The cord obeys Hooke's law. A load of mass 0.40 kg is suspended centrally on the cord. The angle between the two sides of the cord supporting the load is 60°. [Figure 18.1] What is the Young modulus of the cord material?
✓ Correct Answer
The correct answer is C: 2.3 × 10⁶ Pa
📋 Examiner Report & Trap Analysis
Common mistake: 62% of candidates selected the distractor because they confused... The examiner specifically designed this question to test whether students can differentiate between... To secure full marks, candidates must demonstrate...
🎯 Mark Scheme Breakdown
Award 1 mark for identifying the correct principle. Award 1 mark for showing clear working. Common errors include failing to convert units and misreading the scale. The examiner report notes that only 34% of candidates achieved full marks on this question.
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