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O-LevelPhysicsElectricity5054/21 · May/June 2022 · Q67 Marks

A light-dependent resistor (LDR) is used to sense the amount of light in a room. Fig. 6.1 shows part of the circuit used. The LDR is not shown. Complete Fig. 6.1 by drawing the circuit symbol for an LDR between points P and Q.[Figure 6.1]

  1. (a)(i)A light-dependent resistor (LDR) is used to sense the amount of light in a room. Fig. 6.1 shows part of the circuit used. The LDR is not shown. Complete Fig. 6.1 by drawing the circuit symbol for an LDR between points P and Q.[Figure 6.1][1]
  2. (a)(ii)Explain how the voltmeter reading changes as the amount of light falling on the LDR increases.[2]
  3. (b)(i)Fig. 6.2 shows part of a circuit containing three resistors. The current in the 4.0 Ω resistor is 2.4 A. Show that the current in the 5.0 Ω resistor is 1.9 A.[Figure 6.2][2]
  4. (b)(ii)Calculate the potential difference (p.d.) between points X and Y.[2]

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Mark scheme

Marking points from the official mark scheme (May/June 2022). The mark or mark type is shown in brackets.

  1. [1] (a)(i) correct symbol 2 or 3 arrows onto resistor symbol
  2. [1] (a)(ii) resistance (of LDR) decreases
  3. [1] (a)(ii) (voltmeter reading) increases and more current in circuit or potential divider argument comparing voltage across resistor / LDR / voltage of cell
  4. [1] (b)(i) V=IR seen in any form or (voltage across 4 or 5 Ω) 2.4 × 4.0 seen
  5. [1] (b)(i) (I =) 9.6/5 = 1.9(2A)
  6. [1] (b)(ii) (current in 6.0 Ω =) 4.3(2) (A) or (voltage across 6 Ω=) 25.8 or 25.9(2) (V) seen or resistance of parallel resistors = 20/9 (Ω) or total resistance = 8 2/9 (Ω)
  7. [1] (b)(ii) 35 V

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About this question

Topic
Electricity, O-Level Physics (syllabus 5054). Structured question, 7 marks.
Source
O-Level Physics, May/June 2022 Paper 2 Variant 1, question 6.

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