O-LevelPhysicsElectricity5054/22 · May/June 2019 · Q66 Marks
Two lamps, P and Q, are connected to a battery of electromotive force (e.m.f.) 6.0V and an ammeter, as shown in Fig. 6.1. Lamp P has a resistance of 15Ω. The ammeter reading is 0.65A. [Figure 6.1]
- (a)Calculate the current in lamp P.[2]
- (b)Calculate the resistance of lamp Q.[2]
- (c)(i)The two lamps are now connected in series to the ammeter and the same battery. In the space below draw the circuit diagram.[1]
- (c)(ii)The two lamps are now connected in series to the ammeter and the same battery. Explain why the ammeter reading is less than 0.65A when the lamps are connected in series.[1]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (May/June 2019). The mark or mark type is shown in brackets.
- [C1] (I= )V/R algebraic or numerical
- [A1] 0.4(0) A
- [C1] current in Q is 0.25 (A)
- [C1] or (total resistance) 6/0.25 or 6/0.65 or 9.2(3 Ω) seen
- [A1] 24 Ω
- [B1] correct circuit with two lamps ammeter and battery in series
- [B1] (total) resistance increases
- [B1] or (each) lamp has lower p.d. across it
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