Fig. 2.1 shows a container of gas connected to a manometer. The tube in the manometer has a constant cross-sectional area. The gas in the container exerts a pressure. [Figure 2.1]
- (a)Define the term pressure.[1]
- (b)The density of mercury is 1.4 × 10⁴ kg/m³. The gravitational field strength g is 10 N/kg. The pressure of the atmosphere is 1.0 × 10⁵ Pa. Calculate the pressure of the gas in the container.[3]
- (c)(i)In Fig. 2.1, the mercury level on the left-hand side of the manometer is lower than on the right-hand side. The gas inside the container is heated. This causes the mercury levels on both sides to become the same. Determine the mercury level, as shown on the ruler, when this happens.[1]
- (c)(ii)Explain, in terms of the gas molecules, what causes the level of mercury to become the same.[3]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (May/June 2019). The mark or mark type is shown in brackets.
- [B1] force per unit area
- [C1] (P=) dgh algebraic or numerical
- [C1] 0.16 × 1.4 × 10⁴ × 10 or 22 400 (Pa) seen
- [A1] 7.8 x 10⁴ Pa
- [B1] 7.5-8.0 cm
- [B1] (molecules) move faster / have more kinetic energy
- [B1] (molecules) hit sides / walls / mercury / container
- [B1] (molecules) hit harder or more often / more frequently / more violently / vigourously
- [B1] or (molecules) create large(r) pressure / large(r) force
- [B1] or eventually (molecules) exert same pressure as air
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