Fig. 8.1 shows a circuit diagram containing a 2000 Ω resistor of constant resistance and a thermistor. [Figure 8.1]
- (a)(i)At one temperature, the resistance of the thermistor is 1200 Ω. Calculate the potential difference (p.d.) across the 2000 Ω resistor at this temperature.[2]
- (a)(ii)Explain why the p.d. across the 2000 Ω resistor increases when the temperature increases.[2]
- (b)The circuit in Fig. 8.1 can be adapted to enable a lamp to switch on and off automatically. Fig. 8.2 shows the circuit adapted using a relay and Fig. 8.3 shows the circuit adapted using a transistor. [Figure 8.2] [Figure 8.3] In both cases, the lamp switches on when the temperature of the thermistor increases. EITHER Describe what happens inside the relay in Fig. 8.2 that causes the lamp to switch on. OR Describe how the circuit and transistor in Fig. 8.3 cause the lamp to switch on.[2]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (May/June 2019). The mark or mark type is shown in brackets.
- [1] attempt to use potential divider formula or split 12 V in ratio 200:1200 or I = 12/ (2000 + 1200) numerical or algebraic with total resistance
- [1] 7.5 V
- [1] resistance (of thermistor / circuit) falls
- [1] fixed resistor has larger fraction / share of total voltage or voltage across thermistor falls and sum of voltages the same or current in circuit increases (and V = IR explained for fixed resistor)
- [1] (increased current in coil causes) coil / core / relay to become magnetised
- [1] coil/core attracts (iron / magnetic) switch
- [1] transistor switches on / (gives) high (collector) current
- [1] occurs when base and emitter voltage is high (> 0.6 V) or small current into base gives larger output / collector current
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