Measurements are made of the current in a metal wire and the potential difference (p.d.) across it. Fig. 10.1 shows a graph of the current against the p.d. for the wire. [Figure 10.1]
- (a)(i)State the relationship between the current and the p.d. for the metal wire.[1]
- (a)(ii)State how the graph shows that the temperature of the wire does not change in the experiment.[1]
- (a)(iii)1Another wire of the same material has the same length as the original wire but has only half the cross-sectional area. Compare the resistance of the new wire and the original wire.[1]
- (a)(iii)2On Fig. 10.1, draw the graph for the new wire.[1]
- (b)(i)1Three resistors are connected to a d.c. power supply, as shown in Fig. 10.2. The electromotive force (e.m.f.) of the power supply is 6.0 V. Calculate the total resistance of the circuit,[2]
- (b)(i)2the current supplied by the power supply,[2]
- (b)(i)3the p.d. across the 20Ω resistor.[2]
- (b)(ii)1The d.c. power supply is a battery that contains a number of cells. Each cell has an electromotive force (e.m.f.) of 1.5V. State what is meant by the electromotive force (e.m.f.) of a cell.[1]
- (b)(ii)2In the space below, draw a diagram to show how four of these cells are connected to make a battery of e.m.f. 6.0 V. Mark the positive terminal of the battery.[2]
- (b)(ii)3In another arrangement to produce a battery of e.m.f. 6.0V, eight cells of e.m.f. 1.5V are connected. In this arrangement, some cells are connected in series and some in parallel. In the space below, draw a diagram to show how the eight cells are connected to make the battery.[1]
- (c)State one advantage of using a battery made from cells in parallel rather than a single cell.[1]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (May/June 2017). The mark or mark type is shown in brackets.
- [1] directly proportional
- [1] straight line or does not curve or constant gradient
- [1] greater or twice as large
- [1] straight line with half the gradient
- [1] 1/R = 1/R₁+1/R₂ in any form e.g. 1/R=1/20+1/80 or 16 (Ω) seen
- [1] 40 Ω
- [1] (I=)V / R in any form e.g. 6/40
- [1] 0.15 A
- [1] 0.15 x 16 or 0.15 × 24 or 3.6 (V) seen or current split in ratio 1:4, e.g. 0.03 A and 0.12 A seen or clear attempt at potential divider formula
- [1] 2.4 V
- [1] work done ÷ charge
- [1] correct circuit symbol for a cell and positive correct
- [1] four cells, correct symbol, correctly in series
- [1] four cells in series and another four in parallel or any other series and parallel arrangement of 8 cells with connections to and from battery
- [1] lasts longer or if one cell fails it still works or contains more energy
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