A bungee jumper falls from a bridge above a river, as shown in Fig. 11.1. [Figure 11.1 (not to scale)] The man starts from position A in Fig. 11.1. The elastic cord starts to stretch at position C and he stops for the first time at position D. He continues to rise and fall. Fig. 11.2 shows how the velocity of the man varies with time t. [Figure 11.2]
- (a)(i)State what is meant by velocity.[2]
- (a)(ii)State the difference between a positive velocity and a negative velocity.[1]
- (a)(iii) 1.In the first 1.4s the acceleration is uniform. Using values from Fig. 11.2, determine the acceleration of the man in the first 1.4s. acceleration =[3]
- (a)(iii) 2.Comment on your value of acceleration.[1]
- (a)(iv) 1.State the value of t when the man is at position D.[1]
- (a)(iv) 2.Explain, in terms of the forces acting, why the man is accelerating upwards at D.[3]
- (b)(i)Fig. 11.3 shows the values for the gravitational potential energy of the man, the kinetic energy of the man and the elastic potential energy in the cord at A, C and D. You may ignore the effect of air resistance in this question. [Figure 11.3] | | gravitational potential energy/J | kinetic energy/J | elastic potential energy/J | |---|---|---|---| | position A | 20000 | 0 | 0 | | position C | 15000 | | 0 | | position D | 0 | 0 | | Complete Fig. 11.3 to show the kinetic energy of the man at C and the elastic potential energy in the cord at D.[2]
- (b)(ii)The man has a mass of 50 kg. The gravitational field strength g is 10N/kg. Using values from Fig. 11.3, calculate the vertical distance between A and C. distance =[2]
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Mark scheme
Marking points from the official mark scheme (May/June 2015). The mark or mark type is shown in brackets.
- [1] (a) (i) distance (travelled) per second or speed
- distance (travelled) per second/speed in a given direction
- or displacement/time
- or change in displacement per unit time
- or displacement (travelled/covered) per unit time
- [1] (a) (i) or rate of change of displacement
- [1] (a) (ii) opposite direction
- [1] (a) (iii) 1. value seen for v and corresponding value of t
- 0 < t ≤ 1.4 and 0 < v ≤ 14
- [1] (a) (iii) 1. (a=) v-u/t algebraic or numerical equation
- [1] (a) (iii) 1. 10 m/s²
- [1] (a) (iii) 2. sensible comment
- [1] (a) (iv) 1. 4(.0s)
- [1] (a) (iv) 2. weight or force due to gravity mentioned (at D)
- [1] (a) (iv) 2. mention of
- • upwards force (on man) from cord
- • tension / elastic force from cord (on man)
- [1] (a) (iv) 2. force in cord/upward force/tension greater than downwards force
- or resultant force upwards
- [1] (b) (i) 5000
- [1] (b) (i) 20 000
- [1] (b) (ii) (h = ) PE/mg or 5000 = 50 × 10 × h
- [1] (b) (ii) 10 m
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